What is the bandwidth of a 4,800-Hz frequency shift, 9,600-baud ASCII FM transmission?
Answer15.36 kHz
For the specified 9,600-baud ASCII FM signal with a 4,800-Hz shift, the Extra pool gives 15.36 kHz occupied bandwidth.
Amateur Extra · FCC ELEMENT 4
E8C07
Amateur Extra · FCC Element 4 · answer reveals automatically